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Thought of the Day

 Thought of the Day 

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  • We only see that, which our mind is ready to comprehend.  

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Number Mirror | START01

  Problem Write a program that takes a number  N  as the input, and prints it to the output. Input Format The only line contains a single integer. Output Format Output the answer in a single line. Constraints 0 ≤ � ≤ 1 0 5 0 ≤ N ≤ 1 0 5 Sample 1: Input Output 123 123 Sample 2: Input Output 15 15 Solution: #include <iostream> using namespace std; int main() { // your code goes here int n; cin>>n; cout<<n; return 0; }

Sum of Digits | FLOW006

  Problem You're given an integer  N . Write a program to calculate the sum of all the digits of  N . Input Format The first line contains an integer  T , the total number of testcases. Then follow  T  lines, each line contains an integer  N . Output Format For each test case, calculate the sum of digits of  N , and display it in a new line. Constraints 1 ≤ � ≤ 1000 1 ≤ T ≤ 1000 1 ≤ � ≤ 1000000 1 ≤ N ≤ 1000000 Sample 1: Input Output 3 12345 31203 2123 15 9 8 Solution: #include <bits/stdc++.h> using namespace std; int main() {     int t;     cin>>t;     while(t--)     {         int n;         cin>>n;         int sum = 0;         while(n!=0)         {             int r = n%10;             sum+= r;           ...

Valid Triangles | FLOW013

  Problem Write a program to check whether a triangle is valid or not, when the three angles of the triangle are the inputs. A triangle is valid if the sum of all the three angles is equal to 180 degrees. Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains three angles  A ,  B  and  C , of the triangle separated by space. Output Format For each test case, display 'YES' if the triangle is valid, and 'NO', if it is not, in a new line. Constraints 1  ≤   T   ≤  1000 1  ≤   A,B,C   ≤  180 Sample 1: Input Output 3 40 40 100 45 45 90 180 1 1 YES YES NO Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; cin>>t; while(t--){     int a,b,c;     cin>>a>>b>>c;     if((a+b+c)==180)         cout<<"YES"; ...