Amropam Coding

Problem Write a program to find the remainder when an integer  A  is divided by an integer  B . Input The first line contains an integer  T , the total number of test cases. Then  T  lines follow, each line contains two Integers  A  and  B . Output For each test case, find the remainder when  A  is divided by  B , and display it in a new line. Constraints 1  ≤   T   ≤  1000 1  ≤   A,B   ≤  10000 Sample 1: Input Output 3 1 2 100 200 40 15 1 100 10 Solution: #include<iostream> using namespace std; int main(){     int t;     cin>>t;     while(t--){         int a, b;         cin>>a>>b;         cout<<a%b<<endl;     }     return 0; }

  Problem Write a program that takes a number  N  as the input, and prints it to the output. Input Format The only line contains a single integer. Output Format Output the answer in a single line. Constraints 0 ≤ � ≤ 1 0 5 0 ≤ N ≤ 1 0 5 Sample 1: Input Output 123 123 Sample 2: Input Output 15 15 Solution: #include <iostream> using namespace std; int main() { // your code goes here int n; cin>>n; cout<<n; return 0; }

Problem Write a program that takes in a letterclass ID of a ship and display the equivalent string class description of the given ID. Use the table below. Class ID Ship Class B or b BattleShip C or c Cruiser D or d Destroyer F or f Frigate Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains a character. Output Format For each test case, display the Ship Class depending on ID, in a new line. Constraints 1  ≤   T   ≤  1000 Sample 1: Input Output 3 B c D BattleShip Cruiser  Destroyer   Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; char ch; cin>>t; while(t--) { cin>>ch; if(ch=='B' || ch=='b') cout<<"BattleShip"<<endl; if(ch=='C' || ch=='c') cout<<"Cruiser"<<endl; if(ch=='D' || ch=='d') cout<<"Destroyer"<

  Problem Write a program to check whether a triangle is valid or not, when the three angles of the triangle are the inputs. A triangle is valid if the sum of all the three angles is equal to 180 degrees. Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains three angles  A ,  B  and  C , of the triangle separated by space. Output Format For each test case, display 'YES' if the triangle is valid, and 'NO', if it is not, in a new line. Constraints 1  ≤   T   ≤  1000 1  ≤   A,B,C   ≤  180 Sample 1: Input Output 3 40 40 100 45 45 90 180 1 1 YES YES NO Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; cin>>t; while(t--){     int a,b,c;     cin>>a>>b>>c;     if((a+b+c)==180)         cout<<"YES";     else cout<<"NO";     cout<<endl; } return 0; }

Problem Read problem statements in  Mandarin Chinese  and  Russian . You are given a list of  T  integers, for each of them you have to calculate the number of occurrences of the digit  4  in the decimal representation. Input The first line of input consists of a single integer  T , denoting the number of integers in the list. Then, there are  T  lines, each of them contain a single integer from the list. Output Output  T  lines. Each of these lines should contain the number of occurrences of the digit  4  in the respective integer from the list. Constraints 1  ≤  T  ≤  10 5 (Subtask 1):  0  ≤ Numbers from the list ≤  9  - 33 points. (Subtask 2):  0  ≤ Numbers from the list ≤  10 9  - 67 points. Sample 1: Input Output 5 447474 228 6664 40 81 4 0 1 1 0 Explanation: There are four 4s in the  447474 , no 4s in  228 , one 4s in  6664 Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; cin >> t; while(t--){     int i;     cin