Skip to main content

Find Remainder | FLOW002

Problem

Write a program to find the remainder when an integer A is divided by an integer B.

Input

The first line contains an integer T, the total number of test cases. Then T lines follow, each line contains two Integers A and B.

Output

For each test case, find the remainder when A is divided by B, and display it in a new line.

Constraints

  • 1 ≤ T ≤ 1000
  • 1 ≤ A,B ≤ 10000

Sample 1:

Input
Output
3 
1 2
100 200
40 15
1
100
10

Solution:

#include<iostream>
using namespace std;

int main(){
    int t;
    cin>>t;
    while(t--){
        int a, b;
        cin>>a>>b;
        cout<<a%b<<endl;
    }
    return 0;
}

Comments

Popular posts from this blog

Id and Ship | FLOW010

Problem Write a program that takes in a letterclass ID of a ship and display the equivalent string class description of the given ID. Use the table below. Class ID Ship Class B or b BattleShip C or c Cruiser D or d Destroyer F or f Frigate Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains a character. Output Format For each test case, display the Ship Class depending on ID, in a new line. Constraints 1  ≤   T   ≤  1000 Sample 1: Input Output 3 B c D BattleShip Cruiser  Destroyer   Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; char ch; cin>>t; while(t--) { cin>>ch; if(ch=='B' || ch=='b') cout<<"BattleShip"<<endl; if(ch=='C' || ch=='c') cout<<"Cruiser"<<endl; if(ch=='D' || ch=='d') cout<<"Destroyer"<...

Valid Triangles | FLOW013

  Problem Write a program to check whether a triangle is valid or not, when the three angles of the triangle are the inputs. A triangle is valid if the sum of all the three angles is equal to 180 degrees. Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains three angles  A ,  B  and  C , of the triangle separated by space. Output Format For each test case, display 'YES' if the triangle is valid, and 'NO', if it is not, in a new line. Constraints 1  ≤   T   ≤  1000 1  ≤   A,B,C   ≤  180 Sample 1: Input Output 3 40 40 100 45 45 90 180 1 1 YES YES NO Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; cin>>t; while(t--){     int a,b,c;     cin>>a>>b>>c;     if((a+b+c)==180)         cout<<"YES"; ...