Skip to main content

Sum of Digits | FLOW006

 Problem

You're given an integer N. Write a program to calculate the sum of all the digits of N.

Input Format

The first line contains an integer T, the total number of testcases. Then follow T lines, each line contains an integer N.

Output Format

For each test case, calculate the sum of digits of N, and display it in a new line.

Constraints

  • 11000
  • 11000000

Sample 1:

Input
Output
3 
12345
31203
2123
15
9
8

Solution:


#include <bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        int sum = 0;
        while(n!=0)
        {
            int r = n%10;
            sum+= r;
            n /= 10;
        }

        cout<<sum<<endl;
    }

    return 0;
}

Comments

Popular posts from this blog

Number Mirror | START01

  Problem Write a program that takes a number  N  as the input, and prints it to the output. Input Format The only line contains a single integer. Output Format Output the answer in a single line. Constraints 0 ≤ � ≤ 1 0 5 0 ≤ N ≤ 1 0 5 Sample 1: Input Output 123 123 Sample 2: Input Output 15 15 Solution: #include <iostream> using namespace std; int main() { // your code goes here int n; cin>>n; cout<<n; return 0; }

Valid Triangles | FLOW013

  Problem Write a program to check whether a triangle is valid or not, when the three angles of the triangle are the inputs. A triangle is valid if the sum of all the three angles is equal to 180 degrees. Input Format The first line contains an integer  T , the total number of testcases. Then  T  lines follow, each line contains three angles  A ,  B  and  C , of the triangle separated by space. Output Format For each test case, display 'YES' if the triangle is valid, and 'NO', if it is not, in a new line. Constraints 1  ≤   T   ≤  1000 1  ≤   A,B,C   ≤  180 Sample 1: Input Output 3 40 40 100 45 45 90 180 1 1 YES YES NO Solution: #include <iostream> using namespace std; int main() { // your code goes here int t; cin>>t; while(t--){     int a,b,c;     cin>>a>>b>>c;     if((a+b+c)==180)         cout<<"YES"; ...